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9k^2-17k-9=0
a = 9; b = -17; c = -9;
Δ = b2-4ac
Δ = -172-4·9·(-9)
Δ = 613
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{613}}{2*9}=\frac{17-\sqrt{613}}{18} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{613}}{2*9}=\frac{17+\sqrt{613}}{18} $
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